y-3=y^2+9

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Solution for y-3=y^2+9 equation: 



y-3=y^2+9

We move all terms to the left:

y-3-(y^2+9)=0

We get rid of parentheses

-y^2+y-9-3=0

We add all the numbers together, and all the variables

-1y^2+y-12=0

a = -1; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·(-1)·(-12)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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